If x=0.9999…
10x = 9.9999… 10x – x = 9.9999… – 0.9999… 9x = 9 x=1
Therefore 0.9999… = 1
And the universe implodes.
again – stop looking at my fucking maths coursework….there’s three other proofs i can show you that PROVE that 0.9r=1
Firstly, can you think of a number that lies between 0.9r and 1? no…?
^^^
What about 1 divided by 1.1r? Would that just be plain old 0.9?
My maths skills are severely limited, btw. I’m not bad with Venn diagrams, though, provided there are only two circles.
Granted i like this, very smart, and true, but isnt that down to the error of x10 so the decimal point is “moved” one place, to cause the slight difference and rounding im studying maths at A level at the moment, just thought i’d give my view lol
Ummm… This is actually correct and is what happens when you start messing around with infinity.
The other to show this is:
1/3 = 0.33333r 2/3 = 0.66666r
and so… 3/3 = 1 = 0.9999r
or you can just do 1/3 * 3 = 1 == 0.33333r * 3 = 0.99999r
Did a maths degree, albeit not in number theory so I can’t give the formal proof; but it’s on mathworld.wolfram
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again – stop looking at my fucking maths coursework….there’s three other proofs i can show you that PROVE that 0.9r=1
Firstly, can you think of a number that lies between 0.9r and 1? no…?
^^^
What about 1 divided by 1.1r? Would that just be plain old 0.9?
My maths skills are severely limited, btw. I’m not bad with Venn diagrams, though, provided there are only two circles.
Granted i like this, very smart, and true, but isnt that down to the error of x10 so the decimal point is “moved” one place, to cause the slight difference and rounding
im studying maths at A level at the moment, just thought i’d give my view lol
Ummm… This is actually correct and is what happens when you start messing around with infinity.
The other to show this is:
1/3 = 0.33333r
2/3 = 0.66666r
and so… 3/3 = 1 = 0.9999r
or you can just do 1/3 * 3 = 1 == 0.33333r * 3 = 0.99999r
Did a maths degree, albeit not in number theory so I can’t give the formal proof; but it’s on mathworld.wolfram